|
Home
/ FAQ
/ News Classifieds / Events |
Audio Asylum Thread Printer |
Get a view of an entire thread on one page |
66.32.51.100
| '); } else { document.writeln(''); } } else { document.writeln(''); } } else { document.writeln(''); } } // End --> |
In Reply to: RE: There have been many discussions here and elsewhere that posted by hahax@verizon.net on March 21, 2009 at 20:12:55
"Oops there goes every CD player. None of them can sound any good; they alluse op amps, one or two use dicrete device op amps but they're op amps."
I should have made it clear that what I meant was opamps in the form of integrated circuits, not discrete opamps.
CD players that use opamps, especially for IV conversion, probably are not the best. An exception is the Ayre CX-7e, which uses the current-feedback (not the usual voltage-feedback) opamps for the purpose.
JA preferred the Moon over the Parasound JC-2. If the Moon's performance is indeed this impressive it is good news for audiophiles as components can be made at much lower costs with opamps.
Hahax is wrong about needing an op-amp in a CD player. Even a discrete one. There are many that are built with discrete, non-op-amp circuits. Two examples are the Ayre D-1xe DVD player and the Ayre C-5xe MP universal player.
The Ayre CX-7e uses *integrated circuits* to keep the costs down, but they are not op-amps. An op-amp uses feedback as its basic operating principle. The integrated circuits in the Ayre CX-7e (and AX-7e) use no feedback. They are essentially just a collection of transistors in one package.
Charles,
Thanks for the clarification.
Just want to make sure I understand correctly your comment about the CX-7e. The output of the IV circuit is NOT connected to its current input via a resistor, right?
> > The output of the IV circuit is NOT connected to its current input via a resistor, right? < <
None of our circuits in any of products have the output connected back to the input via any connection of any type. That would constitute a feedback loop, which we do not use.
Charles,
I just looked at the datasheet for the integrated circuit. Do you use a resistor connected to pin 5 to set the output voltage? If you do not feel comfortable answering the details I can understand. Thanks.
Yes, access to pin 5 is crucial. It is one of the few IC's that allow access to that node.
Thanks for the info.
Post a Followup: