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In Reply to: RE: Aragon 8008BB (early) 8 ohm & 4 ohm capable posted by Duster on November 12, 2015 at 14:30:02
Thanks, for the reply.
So (just so I can grasp this concept) the amp senses the load from the speakers (either 4 or 8 ohms) and adjusts the power output accordingly ?
Appreciate your counsel, here.
Follow Ups:
There is no adjustment made by the power amplifier. The load determines the current draw necessary for any given end-user's SPL adjustments.
Got it, thanks again !!
Just to clarify: From Ohm's law (E=I*R) and the power equation (P=I*E), we get P = R*I^2. So given that an amplifier is pushing X volts at 8 ohms then if R drops to 4 ohms (R/2), I must double (2I) to produce the same X volts. Substituting we get P= (R/2)* (2I)^2 or 2*(R*I^2), that is the power at 4 ohms is now twice what it was at 8 ohms. Now not every amplifier is able to generate twice the current and so a particular amplifier may produce 200 watts at 8 ohms but only 300 at 4 ohms, not the desired 400. Amplifiers with hefty power supplies like the 8008 can "double down" and are high current amplifiers. This may be important with some speakers, such as Magnepans which have low sensitivity and are power hogs.
Note the power doubling is basically pertinent to SS amps as tube amps use a transformer with multiple taps (4, 8, 16 ohm) to change the voltage so the power remains the same at all settings.
Edits: 11/13/15
That makes sense ... I was confused by the different taps on my tube amps and was looking for something similar on the Aragon.
I appreciate and now understand ...
Thank you !
I reckon the Aragon 8008BB would be a fine choice for the KEF 104/2.
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