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For someone who knows the formula, can you compute for me...
How many watts of Class A would an AB amp have if it had an idling current of 70 mA?
I'm thinking it wouldn't even be 1 watt. Just curious.
Follow Ups:
"idle current need be only one half the peak output current, "
So, 70mA idle will support 140Ma Peak, or 100mA RMS.
W=(I^2)R, so it would be 80mW into 8Ω, half that at 4Ω.
I forgot to note that my inquiry was for a solid state AB amp if that changes things.
> > > "W=(I^2)R, so it would be 80mW into 8Ω, half that at 4Ω." < < <
So less than a tenth of a watt "in" Class A?
Its class B if it cuts off at zero volts. Generally though such amps would have high distortion, so for all practical purposes almost any conventional solid state amp is class AB unless specifically built to be class A.
'Enriched' class A (like class A to 2, 10 or whatever) is still class AB.
It's really not that simple.
Is this a solid state amp, or a tube amp?
Your answer is likely to be very correct for the average solid state amp, but way off for the average tube amp.
It's a solid state amp.
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