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In Reply to: Re: Comparison of a Raw Analog Audio signal to the CD audio and DVD audio output posted by Jim E on September 13, 2006 at 21:28:41:
"UNLESS it is a very long, continuouse sine wave (not music)"That is also blatantly wrong.
There is no requirement for a steady-state signal, much less a sine, in the whole Nyquist-Shannon-Kotelnikow shebang. You may want to dig out
Shannon's formulation of the sampling theorem and his proof. The proof is built entirely on the Fourier transform, which does not preclude transient/finite-time signals as it transforms signals to continuous spectra. (Perhaps you confuse with the Fourier series, which transforms periodic signals to a discrete spectrum.)
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Follow Ups
- Re: Comparison of a Raw Analog Audio signal to the CD audio and DVD audio output - Werner 22:54:59 09/13/06 (2)
- Re: Comparison of a Raw Analog Audio signal to the CD audio and DVD audio output - Jim E 07:20:56 09/14/06 (1)
- Re: Comparison of a Raw Analog Audio signal to the CD audio and DVD audio output - Werner 07:51:10 09/14/06 (0)