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In Reply to: Energy storage (ARC VT100 Mk.II vs. VT130SE) posted by arildji on March 17, 2006 at 03:23:23:
Energy storage means alot. But for what it's worth, when manufacturers start rating their amps by Joules, they're just showing off, trying to sound electrical and dangerous. I think the formula is the working voltage squared times one half of the capacitance in Farads. So, if you have a working voltage of 450V, you square that for 202,500 times any capacitor, say 2000uf, so 1,000 to the-6th will equal 202.5 Joules. So, for any 2,000uF cap operating at 450WV, you have an energy storage of 202.5 Joules.Having sufficient energy storage can mean that you can play louder, longer passages of music without much voltage sag, consequently lower distortion. Also, it can lend 'authority' to bass, though it doesn't actually extend bass response. It can also lower the noise floor in any component, and the higher the number the lower the hum, but not necessarily hiss, directly.
As for difficult speaker loads, I don't know. All things being equal, I think the difference in energy storage may be viewed in this way. Given two combs, both with 25 teeth per inch, one is six inches long, the other is twenty-four inches long. Which will be better to part your hair? (depending on whether or not you have hair. I don't have much left, but I remember such things and it seems to me that the image is about right. ) It seems to me that when you talk about energy storage and difficult speaker loads, you are talking about the length of the comb rather than number of teeth per inch. A stable amp with little energy storage will do much better than an unstable amp with a large capacitor bank. I don't think any of the amps you mentioned fall into the unstable category. I don't know...I could be wrong.
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- Re: Energy storage (ARC VT100 Mk.II vs. VT130SE) - corerosin 11:27:48 03/17/06 (0)