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General Asylum General audio topics that don't fit into specific categories. |
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In Reply to: I have the answer posted by Bill the K on October 6, 2014 at 06:23:31:
I intuited that the answer lay in the concept you said (the ratio of the distance of the load to the opposite side of the triangle to the distance of the support to the same side) but I didn't know how to express it, mathematically.
OK, so:
* 4.30 @ A
* 2.61 @ B, and
* 1.53 @ C.
That was the simple case! :-)) For the real-life situation, we need to get more complicated ... and allow for the added affect of 2 arm weights near B and C!! :-))
See my modified sketch:
It seems to me that if the arms were placed at apex B (arm weight = 0.99 lb) and apex C (arm weight = 1.65 lb) then the weight distribution would simply become:
* 4.30 @ A
* 3.60 @ B, and
* 3.18 @ C.
But because the arms are cantilevered out from B & C, there is a negative action on the apex which is at the other end of the particular triangle side?
So:
* the 0.99 lb arm outboard from B reduces the weight at C, and
* the 1.65 lb arm outboard from C reduces the weight at A?
But how to calculate the resulting apex totals, with these cantilevered weights? :-))
FYI, here is a pic of the 1st version of my 'SkeletaLinn' subchassis - which I completed in July, last year. This has the bearing positioned closer to A, causing an excessive compression of the spring at that apex (so I had to get a custom-made spring made up, which was 30% stiffer than the Linn springs).
Hence the weight analysis for v2! :-))
Thanks, Bill,
Andy
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Follow Ups
- Brilliant, Bill - thank you, thank you! :-)) ... - andyr 13:41:39 10/06/14 (0)
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