In Reply to: RE: Low DCR versus higher inductance chokes posted by xaudiomanx@aol.com on October 5, 2008 at 20:35:14:
The formula for critical inductance is for the input (first part after the diodes) choke. Lc = ((voltage / current) + DCR of choke))/1000
So if your B+ will be 400 and the current draw is 80ma. with a choke that has 60 ohms DCR you need a 5.06Hy choke.
boris' math works out to be almost the same. He's right about using a choke larger than the formula just to make sure.
The DCR of the choke has to do with the value of the caps and the DCR of the power transformer. I don't have a formula for that but the Duncan PSUDII is very helpful.
Too little DCR and the supply will ring (the voltage will not only drop when more current is drawn, it will also "bounce").
Tre'
PS Low DCR is a good thing as long as the ringing can be controlled and other, more important things have not been compromised.
.
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Follow Ups
- RE: Low DCR versus higher inductance chokes - Tre' 21:24:57 10/05/08 (0)