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101.183.7.201
In Reply to: RE: update posted by Tre' on October 18, 2016 at 15:58:25
Maybe not the right place to put this, but am I right in thinking that Paul's rule of thumb formula suggests a lower load than suggested in the WE datasheet?
WE at 300V/0.062A and 740 plate resistance: 3000 Ohm load
Paul's calc for the same operating point (if I am calculating correctly!) suggests 2745 Ohm load. Not a great difference, but could be significant. Maybe WE intentionally selected a slightly lower power, lower distortion load?
Cheers,
91
"Confusion of goals and perfection of means seems to characterise our age." Albert Einstein
Follow Ups:
I didn't check each and every WE operating point but I seem to remember that the ones with the lower HD followed Paul's formula pretty close.BTW 300, 62ma, 740 ohm using Paul's formula gives 3077 ohms
300 /.062=4838.7
2.38 x 740 = 1761.2
4838.7 - 1761.2 = 3077.5
Tre'
Have Fun and Enjoy the Music
"Still Working the Problem"
Edits: 10/19/16
Hi Tre,
Initially I thought is my early morning dyslexia...
Your post states: "Load impedance = (plate to cathode voltage / idle current) - (2.83 x plate resistance)"
Could you please edit the 2.83 to 2.38 for others that read it?
BTW, I have found this thread really helpful. Your explanations for estimating plate resistance and what the curve angles mean have been easy enough for even me to understand.
Thanks,
91.
"Confusion of goals and perfection of means seems to characterise our age." Albert Einstein
.
Have Fun and Enjoy the Music
"Still Working the Problem"
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