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I posted this over on lansingheritage, maybe someone here might know.
I'm wanting to bypass the LPADS on a set of L150's.
They have parts express LPADS installed.
When I measure the LPAD of either the mid or high, straight up 12 o'clock, I get ~19ohms parallel circuit, and ~4.5ohms series circuit.
This thread here
http://www.audioheritage.org/vbulletin/showthread.php?4306-values-on-resistors-in-Lpad-circuit-L96
has a chart for example needing a -3db attenuation, I would need 19.4 & 2.3. I saw another chart online that was about the same thing.
I have an original LPAD that measure 18.5 / 3.5 @ 12 o'clock.
Is it OK to be off +/- a few ohms in an attenuation circuit like this, or is it critical in order for the driver to see 8 ohms?
Also that link explains to remove the hard wired mid band attenuation resistors as well. The L150 has the same mid band attenuation, but I don't see a need to remove them unless the measurement somehow involves that circuit as well?
Follow Ups:
Adjust the L-pad until it sounds best, then measure the values, order the closest higher values, then parallel with smaller higher values until you get them spot on.
Thanks yes I have done that.
What I really need to know is, I'm coming up with 19ohms on the parallel circuit, and 4.5ohms on the series circuit.
I'm wondering how close this balance need to be.
For example, let's say I end up using 19 and 2.5 (instead of 4.5). Will the 2 ohm difference affect what the driver needs to see? I'm not talking about sonically, I'm more concerned with the driver itself. I ask because I'm seeing on the web different results in the series number based on the parallel number I have now. Hope that made sense.
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